Sederhanakan
( x-² y³)⁴
( x³ y-¹ )-³ ( x² y-² )-¹ =![]()
( x-² y³)⁴
( x³ y-¹ )-³ ( x² y-² )-¹ =
Jawaban:
[tex]1. \: {( {x}^{ - 2} {y}^{ 3} )}^{4} = {x}^{ - 2 \times 4} . \: {y}^{3 \times 4} \\ = {x}^{ - 8} {y}^{12} \\ 2.{( {x}^{3} {y}^{ - 1} )}^{ - 3} {( {x}^{2}{y}^{ - 2})}^{ - 1} \\ = {x}^{3 \times ( - 3)} {y}^{ - 1 \times ( - 3)} . \: {x}^{2 \times ( - 1)} {y}^{ - 2 \times ( - 1)} \\ = {x}^{ - 9} {y}^{3} . \: {x}^{ - 2} {y}^{2} \\ = {x}^{ - 9 \times ( - 2)} {y}^{3 \times 2} \\ = {x}^{18} {y}^{6} [/tex]
Penjelasan dengan langkah-langkah:
maaf jika jawabannya salah
[answer.2.content]
